Electromagnetic Induction and Alternating Current 4 Question 8

8. In the circuit shown here, the point $C$ is kept connected to point $A$ till the current flowing through the circuit becomes constant. Afterward, suddenly point $C$ is disconnected from point $A$ and connected to point $B$ at time $t=0$. Ratio of the voltage across resistance and the inductor at $t=L / R$ will be equal to

(2014 Main)

(a) $\frac{e}{1-e}$

(b) 1

(c) -1

(d) $\frac{1-e}{e}$

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Answer:

Correct Answer: 8. (c)

Solution:

  1. After connecting $C$ to $B$ hanging the switch, the circuit will act like an $L-R$ discharging circuit.

Applying Kirchhoff’s loop

equation,

$$ V _R+V _L=0 \Rightarrow V _R=-V _L \Rightarrow \frac{V _R}{V _L}=-1 $$



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