Electromagnetic Induction and Alternating Current 1 Question 6
####6. The figure shows certain wire segments joined together to form a coplanar loop. The loop is placed in a perpendicular magnetic field in the direction going into the plane of
the figure. The magnitude of the field increases with time. $I_{1}$ and $I_{2}$ are the currents in the segments $a b$ and $c d$. Then,
(2009)
(a) $I_{1}>I_{2}$
(b) $I_{1}<I_{2}$
(c) $I_{1}$ is in the direction $b a$ and $I_{2}$ is in the direction $c d$.
(d) $I_{1}$ is in the direction $a b$ and $I_{2}$ is in the direction $d c$.
Show Answer
Answer:
Correct Answer: 6. (d)
Solution:
- Cross $\otimes$ magnetic field passing from the closed loop is increasing. Therefore, from Lenz’s law induced current will produce dot $\odot$ magnetic field. Hence, induced current is anti-clockwise.
