Electromagnetic Induction and Alternating Current 1 Question 5

5. A circular loop of radius 0.3cm lies parallel to a much bigger circular loop of radius 20cm. The centre of the smaller loop is on the axis of the bigger loop. The distance between their centres is 15cm. If a current of 2.0A flows through the bigger loop, then the flux linked with smaller loop is

(2013 Main)

(a) 9.1×1011Wb

(b) 6×1011Wb

(c) 3.3×1011Wb

(d) 6.6×109Wb

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Answer:

Correct Answer: 5. (a)

Solution:

  1. Magnetic field at the centre of smaller loop

B=μ0iR222(R22+x2)3/2

Area of smaller loop S=πR12

Flux through smaller loop φ=BS

Substituting the values, we get, φ9.1×1011Wb



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