Electromagnetic Induction and Alternating Current 1 Question 2

2. A $10 m$ long horizontal wire extends from North-East to South-West. It is falling with a speed of $5.0 ms^{-1}$ at right angles to the horizontal component of the earth’s magnetic field of $0.3 \times 10^{-4} Wb / m^{2}$. The value of the induced emf in wire is

(a) $1.5 \times 10^{-3} V$

(b) $1.1 \times 10^{-3} V$

(c) $0.3 \times 10^{-3} V$

(d) $2.5 \times 10^{-3} V$

(Main 2019, 12 Jan II)

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Answer:

Correct Answer: 2. (a)

Solution:

  1. Wire falls perpendicularly to horizontal component of earth’s magnetic field, so induced electromotive force $(\varepsilon)$ $=B l v$

Substituting the given values, we get

$$ \varepsilon=0.3 \times 10^{-4} \times 10 \times 5=1.5 \times 10^{-3} V $$



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