Current Electricity 1 Question 8
8. A uniform metallic wire has a resistance of $18 \Omega$ and is bent into an equilateral triangle. Then, the resistance between any two vertices of the triangle is
(2019 Main, 10 Jan I)
(a) $12 \Omega$
(b) $8 \Omega$
(c) $2 \Omega$
(d) $4 \Omega$
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Solution:
- Resistance of each arm of equilateral triangle will be
$$ R=\frac{18}{3}=6 \Omega $$
So we have following combination will be
Equivalent resistance is
$$ \therefore \quad R _{A B}=\frac{12 \times 6}{12+6}=\frac{12 \times 6}{18}=4 \Omega $$
