Centre of Mass 3 Question 1

1. A man (mass =50kg ) and his son (mass =20kg ) are standing on a frictionless surface facing each other. The man pushes his son, so that he starts moving at a speed of 0.70ms1 with respect to the man. The speed of the man with respect to the surface is

(2019 Main, 12 April I)

(a) 0.28ms1

(b) 0.20ms1

(c) 0.47ms1

(d) 0.14ms1

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Answer:

Correct Answer: 1. (b)

Solution:

  1. The given situation can be shown as below

Using momentum conservation law,

=( Total momentum )after collision 

(m1×0)+(m2×0)=m1v1+m2v20=m1(v1)i^+m2v2i^

m1v1=m2v250v1=20v2v2=2.5v1

Again, relative velocity =0.70m/s

But from figure, relative velocity =v1+v2

v1+v2=0.7

From Eqs. (i) and (ii), we get

v1+2.5v1=0.7

v1(3.5)=0.7

v1=0.73.5=0.20m/s



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