Vectors 3 Question 26

26. If X→⋅A→=0,X→⋅B→=0,X→⋅C→=0 for some non-zero vector X→, then [A→B→C→]=0.

(1983, 1M)

Show Answer

Answer:

Correct Answer: 26. True

Solution:

  1. Since, X→⋅A→=X→⋅B→=X→⋅C→=0

⇒X→ is perpendicular to A→,B→,C→, therefore [A→B→C→]=0

Hence, given statement is true.

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