Vectors 1 Question 28

29. In a OAB,E is the mid-point of BO and D is a point on AB such that AD:DB=2:1. If OD and AE intersect at P, determine the ratio OP:PD using methods.

(1989,4M)

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Answer:

Correct Answer: 29. (3:2)

  1. Let O be origin and OA=a,OB=b

OE=b2

[since E being mid-point of OB ]

OD=a1+b21+2

(since, D divides AB in the ratio of 2:1 )

Equation of OD is r=t(a+2b3)

and equation of AE is r=a+s(b2a)

If OD and AE intersect at P, then there must be some r for which they are equal.

t(a+2b3)=a+s(b2a)t3=1s and 2t3=s2t=35 and s=45 Point P is a+2b5.

Since, P divides OD in the ratio of λ:1.

λ(a+2b3)+10λ+1=(a+2b5)

From Eqs. (i) and (ii),

λ3(λ+1)=155λ=3λ+3λ=32OPPD=32



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