Trigonometrical Equations 1 Question 19

19. Let α and β be non zero real numbers such that 2(cosβcosα)+cosαcosβ=1. Then which of the following is/are true?

(2017 Adv.)

(a) 3tanα2tanβ2=0

(b) tanα23tanβ2=0

(c) tanα2+3tanβ2=0

(d) 3tanα2+tanβ2=0

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Answer:

Correct Answer: 19. (b, c)

Solution:

  1. We have, 2(cosβcosα)+cosαcosβ=1

 or 4(cosβcosα)+2cosαcosβ=21cosα+cosβcosαcosβ=3+3cosα3cosβ3cosαcosβ(1cosα)(1+cosβ)=3(1+cosα)(1cosβ)(1cosα)(1+cosα)=3(1cosβ)1+cosβtan2α2=3tan2β2tanα2±3tanβ2=0



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