SATHEE: Theory of Equations 1 Question 39

Theory of Equations 1 Question 39

40. If the products of the roots of the equation $x^{2} - 3 k x + 2 e^{2 \log k} - 1 = 0$ is 7 , then the roots are real for $k = \dots$ .

(1984, 2M)

Show Answer

Answer:

Correct Answer: 40. (k=2)

Solution:

Since, $x^{2} - 3 k x + 2 e^{2 \log k} - 1 = 0$ has product of roots 7 .

$\Rightarrow 2 e^{2 \log k} - 1 = 7$

$\Rightarrow e^{2 \log_{e} k} = 4$

$\Rightarrow k^{2} = 4$

$\Rightarrow k = 2 [neglecting - 2]$

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Theory of Equations 1 Question 39

40. If the products of the roots of the equation x2−3kx+2e2log⁡k−1=0 is 7 , then the roots are real for k=….

Answer:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu

40. If the products of the roots of the equation $x^{2} - 3 k x + 2 e^{2 \log k} - 1 = 0$ is 7 , then the roots are real for $k = \dots$ .