SATHEE: Straight Line and Pair of Straight Lines 2 Question 3

Straight Line and Pair of Straight Lines 2 Question 3

3.

Let $P = (- 1, 0)$ , and $Q (0, 0)$ and $R = (3, 3 \sqrt{3})$ be three point. Then, the equation of the bisector of the angle $P Q R$ is

$(2001, 1 M)$

(a) $\frac{\sqrt{3}}{2} x + y = 0$

(b) $x + \sqrt{3} y = 0$

(d) $x + \frac{\sqrt{3}}{2} y = 0$

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Answer:

Correct Answer: 3. (c)

Solution:

The line segment $Q R$ makes an angle of $60^{\circ}$ with the positive direction of $X$ -axis.

So, the bisector of the angle $P Q R$ will make an angle of $60^{\circ}$ with the negative direction of $X$ -axis it will therefore have angle of inclination of $120^{\circ}$ and so, its equation is

$\begin{aligned} y - 0 = \tan 120^{\circ} (x - 0) \\ \Rightarrow & y = - \sqrt{3} x \\ \Rightarrow & y + \sqrt{3} x = 0 \end{aligned}$

Straight Line and Pair of Straight Lines 2 Question 3

3.

Answer:

Engineering Preparation

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Straight Line and Pair of Straight Lines 2 Question 3

3.

Answer:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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