Sequences and Series 3 Question 2

2. If three distinct numbers a,b and c are in GP and the equations ax2+2bx+c=0 and dx2+2ex+f=0 have a common root, then which one of the following statements is correct?

(2019 Main, 8 April II)

(a) d,e and f are in GP

(b) da,eb and fc are in AP

(c) d,e and f are in AP

(d) da,eb and fc are in GP

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Answer:

Correct Answer: 2. (b)

Solution:

  1. (b) Given, three distinct numbers a,b and c are in GP. b2=ac and the given quadratic equations

ax2+2bx+c=0dx2+2ex+f=0

For quadratic Eq. (ii), the discriminant D=(2b)24ac

=4(b2ac)=0

Quadratic Eq. (ii) have equal roots, and it is equal to x=ba, and it is given that quadratic Eqs. (ii) and (iii) have a common root, so

dba2+2eba+f=0db22eba+a2f=0[b2=ac]d(ac)2eab+a2f=0[a0]dc2eb+af=02eb=dc+af2eb=dcb2+afb22eb=da+fc[b2=ac]

So, da,eb,fc are in AP.

Alternate Solution

Given, three distinct numbers a,b and c are in GP. Let a=a,b=ar,c=ar2 are in GP, which satisfies ax2+2bx+c=0

ax2+2(ar)x+ar2=0x2+2rx+r2=0(x+r)2=0x=r.

According to the question, ax2+2bx+c=0 and dx2+2ex+f=0 have a common root.

So, x=r satisfies dx2+2ex+f=0

d(r)2+2e(r)+f=0

dr22er+f=0

dca2ecb+f=0

da2eb+fc=0

da+fc=2eb

[c0]



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