Sequences and Series 3 Question 10

10.

Let α,β be the roots of x2x+p=0 and γ,δ be the roots of x24x+q=0. If α,β,γ,δ are in GP, then the integer values of p and q respectively are

(2001, 1M)

(a) 2,32

(b) 2,3

(c) 6,3

(d) 6,32

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Answer:

Correct Answer: 10. (a)

Solution:

α+β=1 and λ+δ=4

Let r be the common ratio.

Since, α,β, γ and δ are in GP.

Therefore, β=αr,γ=αr2

and δ=αr3

Then, α+αr=1α(1+r)=1

and αr2+αr3=4αr2(1+r)=4

From Eqs. (i) and (ii), r2=4r=±2

Now,

ααr=p and αr2αr3=q

On putting

r=2, we get 

α=1,p=2 and q=32

Again putting r=2, we get α=1/3 and p=29

Since, q and p are integers.

Therefore, we take p=2 and q=32.



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