Sequences and Series 2 Question 5

6. n1,n2,,np are p positive integers, whose sum is an even number, then the number of odd integers among them is odd.

(1985, 1M)

Integer Answer Type Question

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Answer:

Correct Answer: 6. (a)

Solution:

  1. Clearly, the two digit number which leaves remainder 2 when divided by 7 is of the form N=7k+2 [by Division Algorithm]

For,

k=2,N=16k=3,N=23k=13,N=93

12 such numbers are possible and these numbers forms an AP.

Now,

S=122[16+93]=654Sn=n2(a+l)

Similarly, the two digit number which leaves remainder 5 when divided by 7 is of the form N=7k+5

For k=1,N=12

k=2,N=19k=13,N=96

13 such numbers are possible and these numbers also forms an AP.

Now,

S=132[12+96]=702Sn=n2(a+l)

Total sum =S+S=654+702=1356



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