Properties of Triangles 2 Question 11

11. Consider the following statements concerning a ABC (i) The sides a,b,c and area of triangle are rational.

(ii) a,tanB2,tanC2 are rational.

(iii) a,sinA,sinB,sinC are rational.

 Prove that (i)  (ii)  (iii)  (i) 

(1994, 5M)

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Solution:

  1. It is given that a,b,c and area of triangle are rational.

We have, tanB2=(sc)(sa)s(sb)

=s(sa)(sb)(sc)s(sb)

Again, a,b,c are rational given, s=a+b+c2 are rational, Also, (sb) is rational, since triangle is rational, therefore we get

tanB2=Δs(sb) is rational. 

Similarly, tanC2=Δs(sc) is rational.

Therefore a,tanB2,tanC2 are rational.

which shows that, (i) (ii).

Again, it is given that, a,tanB2,tanC2 are rational, then

tanA2=tanπ2B+C2

=cotB+C2=1tanB2+C2=1tanB2tanC2tanB2+tanC2

Since, tan(B/2) and tan(C/2) are rational, hence tan(A/2) is a rational.

Now, sinA=2tanA/21+tan2A/2 as tan(A/2) is a rational number, sinA is a rational. Similarly, sinB and sinC are. Thus, a,sinA,sinB,sinC are rational, therefore (ii) (iii).

Again, a,sinA,sinB,sinC are rational.

By the sine rule,

asinA=bsinB=csinCb=asinBsinA and c=asinCsinA

Since a,sinA,sinB and sinC are rational,

Hence, b and c are also rational.

Also, Δ=12bcsinA

As b,c and sinA are rational, so triangle is rational number. Therefore, a,b,c and triangle are rational.

Therefore, (iii) (i).



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