Probability 1 Question 17

25. An unbiased die, with faces numbered 1, 2, 3, 4, 5 and 6 is thrown n times and the list of n numbers showing up is noted. What is the probability that among the numbers 1, 2, 3, 4, 5 and 6 only three numbers appear in this list?

(2001, 5M)

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Answer:

Correct Answer: 25. (3n32n+3)×6C36n

Solution:

  1. Let us define a onto function F from A:[r1,r2,,rn] to B:[1,2,3], where r1,r2,,rn are the readings of n throws and 1,2,3 are the numbers that appear in the n throws.

Number of such functions, M=N[n(1)n(2)+n(3)] where, N= total number of functions and n(t)= number of function having exactly t elements in the range.

 Now, N=3n,n(1)=32n,n(2)=3,n(3)=0M=3n32n+3

Hence, the total number of favourable cases

=(3n32n+3)6C3 Required probability =(3n32n+3)×6C36n



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