Permutations and Combinations 3 Question 13
13. Total number of ways in which six ’ + ’ and four ’ - ’ signs can be arranged in a line such that no two ‘-‘signs occur together is… .
$(1988,2 M)$
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Answer:
Correct Answer: 13. (35 ways)
Solution:
- Since, six ’ + ’ signs are ++++++
$\therefore 4$ negative sign has seven places to be arranged in
$ \Rightarrow \quad{ }^{7} C _4 \text { ways }=35 \text { ways } $
