Permutations and Combinations 3 Question 13

13. Total number of ways in which six ’ + ’ and four ’ - ’ signs can be arranged in a line such that no two ‘-‘signs occur together is… .

$(1988,2 M)$

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Answer:

Correct Answer: 13. (35 ways)

Solution:

  1. Since, six ’ + ’ signs are ++++++

$\therefore 4$ negative sign has seven places to be arranged in

$ \Rightarrow \quad{ }^{7} C _4 \text { ways }=35 \text { ways } $



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