Permutations and Combinations 2 Question 19

19. A committee of 12 is to be formed from 9 women and 8 men. In how many ways this can be done if at least five women have to be included in a committee? In how many of these committees

(i) the women are in majority?

(ii) the men are in majority?

(1994, 4M)

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Answer:

Correct Answer: 19. 6062 , (i) 2702 (ii) 1008

Solution:

  1. Given that, there are 9 women and 8 men, a committee of 12 is to be formed including at least 5 women.

This can be done in

=(5 women and 7men)+(6 women and 6men)

+(7 women and 5 men )+(8 women and 4 men ) + (9 women and 3 men) ways

Total number of ways of forming committee

=(9C58C7)+(9C68C6)+(9C78C5)+(9C88C4)+(9C98C3)=1008+2352+2016+630+56=6062

(i) The women are in majority =2016+630+56

=2702

(ii) The man are in majority =1008 ways



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