Parabola 3 Question 7

7. The tangent PT and the normal PN to the parabola y2=4ax at a point P on it meet its axis at points T and N, respectively. The locus of the centroid of the triangle PTN is a parabola, whose

(2009)

(a) vertex is 2a3,0

(b) directrix is x=0

(c) latusrectum is 2a3

(d) focus is (a,0)

Integer Answer Type Question

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Answer:

Correct Answer: 7. (a,d)

Solution:

  1. Let P(α,β) be any point on the locus. Equation of pair of tangents from P(α,β) to the parabola y2=4ax is

[βy2a(x+α)]2=(β24aα)(y24ax)

[T2=SS1]

β2y2+4a2(x2+α2+2xα)4aβy(x+α)

=β2y24β2ax4aαy2+16a2αx

β2y2+4a2x2+4a2α2+8xαa2

=β2y24β2ax4aαy2+16a2αx4aβxy4aβαy (i)

Now, coefficient of x2=4a2

coefficient of xy=4aβ

coefficient of y2=4aα

Again, angle between the two of Eq. (i) is given as 45

tan45=2h2aba+b1=2h2aba+ba+b=2h2ab(a+b)2=4(h2ab)(4a2+4aα)2=4[4a2β2(4a2)(4aα)]16a2(a+α)2=44a2[β24aα]α2+6aα+a2β2=0(α+3a)2β2=8a2

Thus, the required equation of the locus is (x+3a)2y2=8a2 which is a hyperbola.



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