Matrices and Determinants 4 Question 17

18. The number of $3 \times 3$ matrices $A$ whose entries are either $0$ or $1$ and for which the system

$A$$ \begin{bmatrix} x \\ y \\ z \end{bmatrix} $ =$ \begin{bmatrix} 1 \\ 0 \\ 0 \end{bmatrix} $ has exactly two distinct solutions, is

(2010)

(a) 0

(b) $2^{9}-1$

(c) 168

(d) 2

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Answer:

Correct Answer: 18. (a)

Solution:

  1. Since, $A$$ \begin{bmatrix} x \\ y \\ z \end{bmatrix} $ =$ \begin{bmatrix} 1 \\ 0 \\ 0 \end{bmatrix} $ is linear equation in three variables and that could have only unique, no solution or infinitely many solution.

$\therefore$ It is not possible to have two solutions.

Hence, number of matrices $A$ is zero.



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