SATHEE: Matrices and Determinants 2 Question 27

Matrices and Determinants 2 Question 27

30. The solution set of the equation $| \begin{matrix} 1 & 4 & 20 \\ 1 & - 2 & 5 \end{matrix} | = 0$ is…

(1981, 2M)

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Answer:

Correct Answer: 30. (-1 ,2)

Solution:

Given, $| \begin{matrix} 1 & 4 & 20 \\ 1 & - 2 & 5 \\ 1 & 2 x & 5 x^{2} \end{matrix} | = 0$

$\Rightarrow 1 (- 10 x^{2} - 10 x) - 4 (5 x^{2} - 5) + 20 (2 x + 2) = 0$

$\Rightarrow - 30 x^{2} + 30 x + 60 = 0$

$\Rightarrow (x - 2) (x + 1) = 0$

$\Rightarrow x = 2, - 1$

Hence, the solution set is $- 1, 2$ .

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Matrices and Determinants 2 Question 27

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30. The solution set of the equation $| \begin{matrix} 1 & 4 & 20 \\ 1 & - 2 & 5 \end{matrix} | = 0$ is…