Limit Continuity and Differentiability 1 Question 11

12. limh0f(2h+2+h2)f(2)f(hh2+1)f(1), given that f(2)=6 and f(1)=4,

(2003, 2M)

(a) does not exist

(b) is equal to 3/2

(c) is equal to 3/2

(d) is equal to 3

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Answer:

Correct Answer: 12. (d)

Solution:

  1. Let y=f(1+x)1/xf(1)logy=1x[logf(1+x)logf(1)]

limx0logy=limx01f(1+x)f(1+x)

=f(1)f(1)=63

[using L’ Hospital’s rule]

loglimx0y=2limx0y=e2



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