Inverse Circular Functions 2 Question 8
8. The principal value of $\sin ^{-1} \sin \frac{2 \pi}{3}$ is
(1986, 2M)
(a) $-\frac{2 \pi}{3}$
(b) $\frac{2 \pi}{3}$
(c) $\frac{\pi}{3}$
(d) $\frac{5 \pi}{3}$
Match the Columns
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Answer:
Correct Answer: 8. (c)
Solution:
- $\sin ^{-1} \sin \frac{2 \pi}{3}=\sin ^{-1} \sin \pi-\frac{\pi}{3}$
$ =\sin ^{-1} \sin \frac{\pi}{3}=\frac{\pi}{3} $
