Indefinite Integration 3 Question 10

10. Let f:(0,)R and F(x)=0xf(t)dt.

If F(x2)=x2(1+x), then f(4) equals

(a) 54

(b) 7

(c) 4

(d) 2

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Answer:

Correct Answer: 10. (c)

Solution:

  1. Given, F(x)=0xf(t)dt

By Leibnitz’s rule,

F(x)=f(x)

But F(x2)=x2(1+x)=x2+x3

[given]

F(x)=x+x3/2F(x)=1+32x1/2f(x)=F(x)=1+32x1/2 [from Eq. (i)] f(4)=1+32(4)1/2f(4)=1+32×2=4



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