Indefinite Integration 1 Question 56

57. The value of 137ππsin(πlogx)xdx is

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Solution:

  1. Let I=137ππsin(πlogx)xdx

Put πlogx=t

πxdx=dt

I=037πsin(t)dt=[cost]037π=[cos37πcos0]

=[(1)1]=2



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