Indefinite Integration 1 Question 45

46. Good approximation of $\int _0^{\pi / 2} \sin x d x$, is

(a) $\pi / 4$

(b) $\pi(\sqrt{2}+1) / 4$

(c) $\pi(\sqrt{2}+1) / 8$

(d) $\frac{\pi}{8}$

Objective Questions II

(One or more than one correct option)

Show Answer

Solution:

  1. $\int _0^{\pi / 2} \sin x d x=\frac{\frac{\pi}{2}-0}{4} \sin 0+\sin \frac{\pi}{2}+2 \sin \frac{0+\frac{\pi}{2}}{2}$

$$ =\frac{\pi}{8}(1+\sqrt{2}) $$



NCERT Chapter Video Solution

Dual Pane