Indefinite Integration 1 Question 25

26. The integral 1/21/2[x]+log1+x1xdx equals(2002, 1M)

(a) 12

(b) 0

(c) 1

(d) log12

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Solution:

  1. 1/21/2[x]+log1+x1xdx

=1/21/2[x]dx+1/21/2log1+x1xdx

=1/21/2[x]dx+0log1+x1x is an odd function

=1/20[x]dx+01/2[x]dx=1/20(1)dx+01/2(0)dx

=[x]1/20=0+12=12



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