Hyperbola 3 Question 2

2.

If the circle x2+y2=a2 intersects the hyperbola xy=c2 in four points P(x1,y1),Q(x2,y2),R(x3,y3),S(x4,y4), then

(1998,2M) (a) x1+x2+x3+x4=0

(b) y1+y2+y3+y4=0

(c) x1x2x3x4=c4

(d) y1y2y3y4=c4

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Answer:

Correct Answer: 2. (a,b,c,d)

Solution:

  1. It is given that,

x2+y2=a2

and xy=c2

We obtain x2+c4/x2=a2

x4a2x2+c4=0

Now, x1,x2,x3,x4 will be roots of Eq. (iii).

Therefore, Σx1=x1+x2+x3+x4=0 and product of the roots x1x2x3x4=c4

Similarly, y1+y2+y3+y4=0

and y1y2y3y4=c4

Hence, all options are correct.



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