Hyperbola 1 Question 11

12. If $e _1$ is the eccentricity of the ellipse $\frac{x^{2}}{16}+\frac{y^{2}}{25}=1$ and $e _2$ is the eccentricity of the hyperbola passing through the foci of the ellipse and $e _1 e _2=1$, then equation of the hyperbola is

(a) $\frac{x^{2}}{9}-\frac{y^{2}}{16}=1$

(b) $\frac{x^{2}}{16}-\frac{y^{2}}{9}=-1$

(c) $\frac{x^{2}}{9}-\frac{y^{2}}{25}=1$

(d) None of these

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Answer:

Correct Answer: 12. (b)

Solution:

  1. The eccentricity of $\frac{x^{2}}{16}+\frac{y^{2}}{25}=1$ is

$$ \begin{array}{rlrl} e _1 & =\sqrt{1-\frac{16}{25}}=\frac{3}{5} \\ \therefore \quad e _2 & =\frac{5}{3} & {\left[\because e _1 e _2=1\right]} \end{array} $$

$\Rightarrow$ Foci of ellipse $(0, \pm 3)$

$\Rightarrow$ Equation of hyperbola is $\frac{x^{2}}{16}-\frac{y^{2}}{9}=-1$.



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