Definite Integration Question 61
Question 61
- The value of
(1989, 2M)
Show Answer
Solution:
$=\frac{x^{3}}{3}-x_{-2}^{-1}+x-{\frac{x^{3}}{3}}{-1}^{1}+\frac{x^{3}}{3}-x{1}^{2}$
(1989, 2M)
Solution:
$=\frac{x^{3}}{3}-x_{-2}^{-1}+x-{\frac{x^{3}}{3}}{-1}^{1}+\frac{x^{3}}{3}-x{1}^{2}$
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