Definite Integration Question 10

Question 10

  1. Let f:(0,)R and F(x)=0xf(t)dt.

If F(x2)=x2(1+x), then f(4) equals (a) 54 (b) 7 (c) 4 (d) 2

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Answer:

Correct Answer: 10. (c)

Solution:

  1. Given, F(x)=0xf(t)dt

By Leibnitz’s rule,

F(x)=f(x)

But F(x2)=x2(1+x)=x2+x3

[given]

F(x)=x+x3/2F(x)=1+32x1/2 f(x)=F(x)=1+32x1/2 [from Eq. (i)]  f(4)=1+32(4)1/2f(4)=1+32×2=4



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