Complex Numbers 5 Question 9

10. If ω is an imaginary cube root of unity, then (1+ωω2)7 is equal to

(a) 128w

(b) 128ω

(c) 128ω2

(d) 128ω2

(1998, 2M)

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Answer:

Correct Answer: 10. (d)

Solution:

  1. (1+ωω2)7=(ω2ω2)7

[1+ω+ω2=0]

=(2ω2)7=(2)7ω14=128ω2



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