Complex Numbers 4 Question 19

19.

For any integer k, let αk=coskπ7+isinkπ7, where i=1. The value of the expression

k=112|αk+1αk|k=13|α4k1α4k2| is 

(2016 Adv.)

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Answer:

Correct Answer: 19. (4)

Solution:

  1. Given, αk=coskπ7+isinkπ7

=cos2kπ14+isin2kπ14

αk are vertices of regular polygon having 14 sides.

Let the side length of regular polygon be a.

|αk+1αk|= length of a side of the regular polygon

=a

and |α4k1α4k2|= length of a side of the regular polygon

k=112|αk+1αk|k=13|α4k1α4k2|=12(a)3(a)=4



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