SATHEE: Complex Numbers 1 Question 7

Complex Numbers 1 Question 7

7.

If $| \begin{matrix} 6 i & - 3 i & 1 \\ 4 & 3 i & - 1 \\ 20 & 3 & i \end{matrix} | = x + i y$ , then

(1998, 2M)

(a) $x = 3, y = 1$

(b) $x = 1, y = 1$

(d) $x = 0, y = 0$

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Answer:

Correct Answer: 7. (d)

Solution:

Given, $| \begin{matrix} 6 i & - 3 i & 1 \\ 4 & 3 i & - 1 \\ 20 & 3 & i \end{matrix} | = x + i y$

$\Rightarrow - 3 i | \begin{matrix} 6 i & 1 & 1 \\ 4 & - 1 & - 1 \\ 20 & i & i \end{matrix} | = x + i y$

$\Rightarrow x + i y = 0$

$[∵ C_{2} and C_{3} are identical]$

$\Rightarrow x = 0, y = 0$

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Complex Numbers 1 Question 7

7.

Answer:

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