Circle 4 Question 17

17. Consider the family of circles x2+y2=r2,2<r<5. If in the first quadrant, the common tangent to a circle of this family and the ellipse 4x2+25y2=100 meets the coordinate axes at A and B, then find the equation of the locus of the mid-points of AB.

(1999, 5M)

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Answer:

Correct Answer: 17. 4x2+25y2=4x2y2

Solution:

  1. Equation of any tangent to circle x2+y2=r2 is

xcosθ+ysinθ=r

Suppose Eq. (i) is tangent to 4x2+25y2=100

or x225+y24=1 at (x1,y1)

Then, Eq. (i) and xx125+yy14=1 are identical

x1/25cosθ=y14sinθ=1rx1=25cosθr,y1=4sinθr

The line (i) meet the coordinates axes in A(rsecθ,0) and β(0,rcosecθ). Let (h,k) be mid-point of AB.

Then,

h=rsecθ2 and k=rcosecθ2

Therefore, 2h=rcosθ and 2k=rsinθ

x1=252h and y1=42k

As (x1,y1) lies on the ellipse x225+y24=1, we get

1256254h2+144k2=1 or 254h2+1k2=125k2+4h2=4h2k2

Therefore, required locus is 4x2+25y2=4x2y2



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