Circle 1 Question 16
16. The line $x+3 y=0$ is a diameter of the circle $x^{2}+y^{2}-6 x+2 y=0$.
(1989, 1M)
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Answer:
Correct Answer: 16. True
Solution:
- Since, centre of circle is $(3,-1)$ which lies on $x+3 y=0$
$\Rightarrow \quad x+3 y=0$ is diameter of $x^{2}+y^{2}-6 x+2 y=0$
Hence, given statement is true.
