SATHEE: Circle 1 Question 16

Circle 1 Question 16

16. The line $x + 3 y = 0$ is a diameter of the circle $x^{2} + y^{2} - 6 x + 2 y = 0$ .

(1989, 1M)

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Answer:

Correct Answer: 16. True

Solution:

Since, centre of circle is $(3, - 1)$ which lies on $x + 3 y = 0$

$\Rightarrow x + 3 y = 0$ is diameter of $x^{2} + y^{2} - 6 x + 2 y = 0$

Hence, given statement is true.

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Circle 1 Question 16

16. The line x+3y=0 is a diameter of the circle x2+y2−6x+2y=0.

Answer:

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16. The line $x + 3 y = 0$ is a diameter of the circle $x^{2} + y^{2} - 6 x + 2 y = 0$ .