Binomial Theorem 1 Question 29

31.

The larger of 9950+10050 and 10150 is … .

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Answer:

Correct Answer: 31. (101)50

Solution:

  1. Consider, (101)50(99)50(100)50

=(100+1)50(1001)50(100)50

=(100)50(1+0.01)50(10.01)501

=(100)502[50C1(0.01)+50C3(0.01)3+]1

=(100)502[50C3(0.01)3+50C5(0.01)5+]

(101)50(99)50+(100)50>0

(101)50>(99)50+(100)50



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