Binomial Theorem 1 Question 15

16.

The value of (21C110C1)+(21C210C2) +(21C310C3)+(21C410C4)++(21C1010C10) is

(a) 221211

(b) 221210

(c) 22029

(d) 220210

(2017 Main)

Show Answer

Answer:

Correct Answer: 16. (d)

Solution:

  1. (21C110C1)+(21C210C2)+(21C310C3)

++(21C1010C10)=(21C1+21C2++21C10)(10C1+10C2++10C10)=12(21C1+21C2++21C20)(2101)=12(21C1+21C2++21C211)(2101)=12(2212)(2101)=2201210+1=220210



NCERT Chapter Video Solution

Dual Pane