SATHEE: Area Question 24

Area Question 24

Question 24

The area bounded by the curves $y = (x - 1)^{2}, y = (x + 1)^{2}$ and $y = \frac{1}{4}$ is

(2005, 1M) (a) $\frac{1}{3}$ sq unit (b) $\frac{2}{3}$ sq unit (c) $\frac{1}{4}$ sq unit (d) $\frac{1}{5}$ sq unit

Show Answer

Solution:

The curves $y = (x - 1)^{2}, y = (x + 1)^{2}$ and $y = 1 / 4$ are shown as

where, points of intersection are

$(x - 1)^{2} = \frac{1}{4} \Rightarrow x = \frac{1}{2} and (x + 1)^{2} = \frac{1}{4} \Rightarrow x = - \frac{1}{2}$

i.e.

$Q \frac{1}{2}, \frac{1}{4} and R - \frac{1}{2}, \frac{1}{4}$

$∴$ Required area $= 2 \int_{0}^{1 / 2} (x - 1)^{2} - \frac{1}{4} d x$

$\begin{aligned} = 2 \frac{(x - 1)^{3}}{3} - \frac{1}{4} x^{1 / 2} & = 2 - \frac{1}{8 \cdot 3} - \frac{1}{8} - \frac{1}{3} - 0 = \frac{8}{24} = \frac{1}{3} sq unit \end{aligned}$

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Area Question 24

Question 24

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu