Application of Derivatives 1 Question 18

####18. The curve y=ax3+bx2+cx+5, touches the X-axis at P(2,0) and cuts the Y-axis at a point Q, where its gradient is 3 . Find a,b,c.

(1994, 5M)

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Solution:

  1. Given, y=ax3+bx2+cx+5 touches X-axis at P(2,0) which implies that X-axis is tangent at (2,0) and the curve is also passes through (2,0).

The curve cuts Y-axis at (0,5) and gradient at this point is given 3 , therefore at (0,5) slope of the tangent is 3.

Now,

dydx=3ax2+2bx+c

Since, X-axis is tangent at (2,0).

dydxx=2=00=3a(2)2+2b(2)+c0=12a4b+c

Again, slope of tangent at (0,5) is 3 .

|dydx|(0,5)=33=3a(0)2+2b(0)+c3=c

Since, the curve passes through (2,0).

0=a(2)3+b(2)2+c(2)+50=8a+4b2c+5

From Eqs. (i) and (ii),

12a4b=3

From Eqs. (ii) and (iii),

8a+4b=1

On adding Eqs. (iv) and (v), we get

4a=2a=1/2

On putting a=1/2 in Eq. (iv), we get

12(1/2)4b=364b=33=4bb=3/4a=1/2,b=3/4 and c=3



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