SATHEE: 3D Geometry 3 Question 34

3D Geometry 3 Question 34

####34. The equation of the plane passing through the point $(1, 1, 1)$ and perpendicular to the planes $2 x + y - 2 z = 5$ and $3 x - 6 y - 2 z = 7$ is

(2017 Adv.)

(a) $14 x + 2 y - 15 z = 1$

(b) $- 14 x + 2 y + 15 z = 3$

(d) $14 x + 2 y + 15 z = 31$

Show Answer

Answer:

Correct Answer: 34. (d)

Solution:

Let the equation of plane be $a x + b y + c z = 1$ . Then

$\begin{array}{r} a + b + c = 1 \\ 2 a + b - 2 c = 0 \\ 3 a - 6 b - 2 c = 0 \Rightarrow a = 7 b, c = \frac{15 b}{2} \\ b = \frac{2}{31}, a = \frac{14}{31}, c = \frac{15}{31} \\ ∴ 14 x + 2 y + 15 z = 31 \end{array}$

3D Geometry 3 Question 34

Answer:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

3D Geometry 3 Question 34

Answer:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu