3D Geometry 3 Question 26

####26. The equation of the plane containing the straight line x2=y3=z4 and perpendicular to the plane containing the straight lines x3=y4=z2 and x4=y2=z3 is

(a) 5x+2y4z=0

(b) x+2y2z=0

(c) 3x+2y3z=0

(d) x2y+z=0

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Answer:

(d)

Solution:

  1. Let P1 be the plane containing the lines

x3=y4=z2 and x4=y2=z3

For these two lines, direction vectors are

b1=3i^+4j^+2k^ and b2=4i^+2j^+3k^

A vector along the normal to the plane P1 is given by

n1=b1×b2=|i^j^k^342423|=i^(124)j^(98)+k^(616)=8i^j^10k^

Let P2 be the plane containing the line x2=y3=z4 and perpendicular to plane P1.

For the line x2=y3=z4, the direction vector is b=2i^+3j^+4k^ and it passes through the point with position vector a=0i^+0j^+0k^.

P2 is perpendicular to P1, therefore n1 and b lies along the plane.

Also, P2 also passes through the point with position vector a.

Equation of plane P2 is given by

(ra)(n1×b)=0|x0y0z08110234|=0x(4+30)y(32+20)+z(24+2)=026x52y+26z=0x2y+z=0



NCERT Chapter Video Solution

Dual Pane