Transition and InnerTransition Elements - Result Question 163
####63.
Identify the metal $M$ and hence $M Cl _4$. Explain the difference in colours of $M Cl _4$ and $A$.
(2005)
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Solution:
- $A=\left[Ti\left(H _2 O\right) _6\right]^{3+}$ and $M=Ti, B=TiO _2, Ti(IV)$ has no electron in $3 d$-orbital, no $d$ - $d$ transition is possible, therefore $M Cl _4$ is colourless. In $A$, there is one electron in $3 d$-orbital and its $d-d$ transition is responsible for colour.
