Thermodynamics and Thermochemistry - Result Question 61

####61. The total energy of one mole of an ideal monatomic gas at $27^{\circ} C$ is …cal.

$(1984,1 M)$

True/False

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Solution:

  1. $900 cal: E=\frac{3}{2} R T=\frac{3}{2} \times 2 \times 300 cal$


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