SATHEE: Surface Chemistry - Result Question 16

Surface Chemistry - Result Question 16

####16. Which of the salt-solution is most effective for coagulation of arsenious sulphide?

(2019 Main, 9 Jan II)

(a) $B a C l_{2}$

(b) $A l C l_{3}$

(d) $N a C l$

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Answer:

Correct Answer: 16. $(a, c)$

Solution:

Arsenious sulphide sol is a negative colloid, $A s_{2} S_{3} . (S^{2 -})$ . So, it will be coagulated by the cation of an electrolyte.

According to the Hardy-Schulze rule, the higher the charge of the ion, the more effective it is in bringing about coagulation. Here, the cations available are $A l^{3 +}$ (from $A l C l_{3}$ ), $B a^{2 +}$ (from $B a C l_{2}$ ) and $N a^{+}$ (from $N a_{3} P O_{4}$ and $N a C l$ ). So, their power to coagulate $A s_{2} S_{3}$ . $(S^{2 -})$ will follow the order as

$A l^{3 +} > B a^{2 +} > N a^{+}$

Surface Chemistry - Result Question 16

Answer:

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Surface Chemistry - Result Question 16

Answer:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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