####91. Calculate the average kinetic energy, in joule per molecule in $8.0 g$ of methane at $27^{\circ} C$.
(1982, 2M)
$$ =\frac{3}{2} \times 1.38 \times 10^{-23} \times 300 J=6.21 \times 10^{-21} J / \text { molecule } $$
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