SATHEE: States of Matter - Result Question 35

States of Matter - Result Question 35

####35. The average velocity of an ideal gas molecule at $27^{\circ} C$ is $0.3 m / s$ . The average velocity at $927^{\circ} C$ will be $(1986, 1 M)$

(a) $0.6 m / s$

(b) $0.3 m / s$

(d) $3.0 m / s$

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Solution:

Expression for average velocity is $u_{a v} = \sqrt{\frac{8 R T}{π M}}$

For the same gas but at different temperature

$\begin{aligned} \frac{u_{a v g} (T_{1})}{u_{a v g} (T_{2})} & = \sqrt{\frac{T_{1}}{T_{2}}} = \sqrt{\frac{300}{1200}} = \frac{1}{2} \Rightarrow u_{a v} (927^{\circ} C) & = 2 \times u_{a v} (27^{\circ} C) = 0.6 m s^{- 1} \end{aligned}$

States of Matter - Result Question 35

Solution:

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States of Matter - Result Question 35

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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