States of Matter - Result Question 24
####24. According to Graham’s law, at a given temperature the ratio of the rates of diffusion $\frac{r _A}{r _B}$ of gases $A$ and $B$ is given by (where, $p$ and $M$ are pressures and molecular weights of gases $A$ and $B$ respectively)
(a) $\left(\frac{p _A}{p _B}\right)\left(\frac{M _A}{M _B}\right)^{\frac{1}{2}}$
(b) $\left(\frac{M _A}{M _B}\right)\left(\frac{p _A}{p _B}\right)^{\frac{1}{2}}$
(c) $\left(\frac{p _A}{p _B}\right)\left(\frac{M _B}{M _A}\right)^{\frac{1}{2}}$
(d) $\left(\frac{M _A}{M _B}\right)\left(\frac{p _B}{p _A}\right)^{\frac{1}{2}}$
$(1998,2 M)$
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Solution:
- Rate of effusion $\propto p _i ; p _i=$ Partial pressure of $i$ th component
$$ \propto \sqrt{\frac{1}{M}} $$
