SATHEE: States of Matter - Result Question 13

States of Matter - Result Question 13

####13. For one mole of a van der Waals’ gas when $b = 0$ and $T = 300 K$ , the $p V v s 1 / V$ plot is shown below. The value of the van der Waals’ constant $a$ (atm $L m o l^{- 2})$

(2012)

(a) 1.0

(b) 4.5

(d) 3.0

Show Answer

Solution:

The van der Waals’ equation of state is

$(p + \frac{n^{2} a}{V^{2}}) (V - n b) = n R T$

For one mole and when $b = 0$ , the above equation condenses to

$(p + \frac{a}{V^{2}}) V = R T$

$\Rightarrow p V = R T - \frac{a}{V}$

Eq. (i) is a straight equation between $p V$ and $\frac{1}{V}$ whose slope is c $- a^{'}$ . Equating with slope of the straight line given in the graph.

$\begin{aligned} - a & = \frac{20.1 - 21.6}{3 - 2} = - 1.5 \Rightarrow & a & = 1.5 \end{aligned}$

States of Matter - Result Question 13

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

States of Matter - Result Question 13

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu