SATHEE: States of Matter - Result Question 12

States of Matter - Result Question 12

####12. For gaseous state, if most probable speed is denoted by $C^{*}$ , average speed by $\bar{C}$ and root square speed by $C$ , then for a large number of molecules, the ratios of these speeds are

(a) $C^{*} : \bar{C} : C = 1.225 : 1.128 : 1$

(2013 Main)

(b) $C^{*} : \bar{C} : C = 1.128 : 1.225 : 1$

(d) $C^{*} : \bar{C} : C = 1 : 1.225 : 1.128$

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Solution:

$C^{*} =$ Most probable speed $= \sqrt{\frac{2 R T}{M}}$

$\bar{C} = Average speed = \sqrt{\frac{8 R T}{π M}}$

$C =$ Root square speed corrected as root means square speed, i.e.

rms $= \sqrt{\frac{3 R T}{M}}$ and as we know $\dot{\hat{C}} < \bar{C} < C$

$\overset{*}{C} : \bar{C} : C = 1 : \sqrt{\frac{4}{p}} : \sqrt{\frac{3}{2}} = 1 : 1.128 : 1.225$

NOTE

As no option correspond to root square speed, it is understood as misprint. It should be root mean square speed.

States of Matter - Result Question 12

Solution:

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States of Matter - Result Question 12

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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